Notes
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==85728==ERROR: AddressSanitizer: heap-use-after-free on address 0x616000000380 at pc 0x00000051cb99 bp 0x7ffeda158170 sp 0x7ffeda158168
READ of size 4 at 0x616000000380 thread T0
#0 0x51cb98 (/out/package/cleaner_mem+0x51cb98)
#1 0x7f84dc08bb96 (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
#2 0x41db19 (/out/package/cleaner_mem+0x41db19)
0x616000000380 is located 0 bytes inside of 528-byte region [0x616000000380,0x616000000590)
freed by thread T0 here:
#0 0x516e98 (/out/package/cleaner_mem+0x516e98)
#1 0x51c462 (/out/package/cleaner_mem+0x51c462)
#2 0x7f84dc08bb96 (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
previously allocated by thread T0 here:
#0 0x516140 (/out/package/cleaner_mem+0x516140)
#1 0x51b7a2 (/out/package/cleaner_mem+0x51b7a2)
#2 0x7f84dc08bb96 (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
SUMMARY: AddressSanitizer: heap-use-after-free (/out/package/cleaner_mem+0x51cb98)
Shadow bytes around t
Hints
Your answer may be identical to the JOJ answer in the first several lines.
However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.
Please double check your code to solve this problem and try again.
Your Answer
\par The natural period of oscillation is
\begin{equation}
T=\frac{2 \pi}{\omega_{0}}=2 \pi \sqrt{\frac{M}{k_{1}+k_{2}}}.
\end{equation}
\par Since the mass of spring cannot be ignored, we take the effective mass of the oscillator into account.
It consists of the mass of the object and the effective mass of the spring, which is 1/3 of the actual mass of it. Then the angular frequency can be expressed as
\begin{equation}
\omega_{0}=\sqrt{\frac{k_{1}+k_{2}}{M+m_{0}}},
\end{equation}
where $m_0=\frac{1}{3}m_s$, representing the effective and actual masses of the spring.
\par In harmonic motion in a spring-mass system, the elastic potential energy is $U=kx^2/2$ and the kinetic energy of the oscillating mass $m$ is $K=mv^2/2$.
In the absence of non-conservative for
JOJ Answer
\par The natural period of oscillation is
\begin{equation}
T=\frac{2 \pi}{\omega_{0}}=2 \pi \sqrt{\frac{M}{k_{1}+k_{2}}}.
\end{equation}
\par Since the mass of spring cannot be ignored, we take the effective mass of the oscillator into account.
It consists of the mass of the object and the effective mass of the spring, which is 1/3 of the actual mass of it. Then the angular frequency can be expressed as
\begin{equation}
\omega_{0}=\sqrt{\frac{k_{1}+k_{2}}{M+m_{0}}},
\end{equation}
where $m_0=\frac{1}{3}m_s$, representing the effective and actual masses of the spring.
\par In harmonic motion in a spring-mass system, the elastic potential energy is $U=kx^2/2$ and the kinetic energy of the oscillating mass $m$ is $K=mv^2/2$.
In the absence of non-conservative for
k=\frac{m v_{\max }^{2}}{A^{2}}.
\end{equation}