Record Case Detail

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==34131==ERROR: AddressSanitizer: heap-use-after-free on address 0x6020000000f8 at pc 0x000000515b51 bp 0x7ffc47d0d350 sp 0x7ffc47d0d348
READ of size 4 at 0x6020000000f8 thread T0
    #0 0x515b50  (/out/package/hashtable+0x515b50)
    #1 0x51503a  (/out/package/hashtable+0x51503a)
    #2 0x7fb60239cb96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
    #3 0x41c959  (/out/package/hashtable+0x41c959)

0x6020000000f8 is located 8 bytes inside of 16-byte region [0x6020000000f0,0x602000000100)
freed by thread T0 here:
    #0 0x4dc640  (/out/package/hashtable+0x4dc640)
    #1 0x51509f  (/out/package/hashtable+0x51509f)
    #2 0x7fb60239cb96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

previously allocated by thread T0 here:
    #0 0x4dc810  (/out/package/hashtable+0x4dc810)
    #1 0x515511  (/out/package/hashtable+0x515511)
    #2 0x51503a  (/out/package/hashtable+0x51503a)
    #3 0x7fb60239cb96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

SUMMARY: Address

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

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The value is 24.
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The value is 3.
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The value is 3.
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