Record Case Detail

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==26623==ERROR: AddressSanitizer: heap-use-after-free on address 0x602000000218 at pc 0x000000515b51 bp 0x7fffb4bf03b0 sp 0x7fffb4bf03a8
READ of size 4 at 0x602000000218 thread T0
    #0 0x515b50  (/out/package/hashtable+0x515b50)
    #1 0x51503a  (/out/package/hashtable+0x51503a)
    #2 0x7fa4f9412b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
    #3 0x41c959  (/out/package/hashtable+0x41c959)

0x602000000218 is located 8 bytes inside of 16-byte region [0x602000000210,0x602000000220)
freed by thread T0 here:
    #0 0x4dc640  (/out/package/hashtable+0x4dc640)
    #1 0x51509f  (/out/package/hashtable+0x51509f)
    #2 0x7fa4f9412b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

previously allocated by thread T0 here:
    #0 0x4dc810  (/out/package/hashtable+0x4dc810)
    #1 0x515511  (/out/package/hashtable+0x515511)
    #2 0x51503a  (/out/package/hashtable+0x51503a)
    #3 0x7fa4f9412b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

SUMMARY: Address

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

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JOJ Answer