Record Case Detail

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==15990==ERROR: LeakSanitizer: detected memory leaks

Direct leak of 120 byte(s) in 5 object(s) allocated from:
    #0 0x4dc810  (/out/package/dictionary+0x4dc810)
    #1 0x515553  (/out/package/dictionary+0x515553)
    #2 0x5150dc  (/out/package/dictionary+0x5150dc)
    #3 0x7f1d439afb96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

SUMMARY: AddressSanitizer: 120 byte(s) leaked in 5 allocation(s).

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

0
***Print Dictionary***
Original: {5:4, }.
Reversed: {5:4, }.
****Print Finished****
1
***Print Dictionary***
Original: {5:9, }.
Reversed: {5:9, }.
****Print Finished****
2
The value is 9.
***Print Dictionary***
Original: {5:9, }.
Reversed: {5:9, }.
****Print Finished****
3
***Print Dictionary***
Original: {5:9, }.
Reversed: {5:9, }.
****Print Finished****
4
***Print Dictionary***
Original: {4:8, 5:9, }.
Reversed: {5:9, 4:8, }.
****Print Finished****
5
***Print Dictionary***
Original: {4:8, 5:9, 8:1, }.
Reversed: {8:1, 5:9, 4:8, }.
****Print Finished****
6
***Print Dictionary***
Original: {4:8, 5:9, 7:0, 8:1, }.
Reversed: {8:1, 7:0, 5:9, 4:8, }.
****Print Finished****
7
***Print Dictionary***
Original: {2:2, 4:8, 5:9, 7:0, 8:1, }.
Reversed: {8:1, 7:0, 5:9, 4:8, 2:2, }.
****Print Finished****
8
***Print Dictionary***
Original: {1:7, 2:2, 4:8, 5:9, 7:0, 8:1, }.
Reversed: {8:1, 7:0, 5:9, 4:8, 2:2, 1:7, }.
****Print Finished****
9
***Print Dictionary***
Original: {1:7, 2:2, 4:10, 5:9, 7:0, 8:1, }.
Reversed: {8:1

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