Record Case Detail

This function is in beta test. Please help improve it in the issues here.

5 int
0 append 4AP0LIhQU 143
1 append oBUmdxEaIHuyL8 48582
2 print
=================================================================
==8==ERROR: AddressSanitizer: heap-buffer-overflow on address 0x602000000019 at pc 0x000000448777 bp 0x7fffd802ab00 sp 0x7fffd802a2b0
READ of size 10 at 0x602000000019 thread T0
    #0 0x448776  (/out/package/main+0x448776)
    #1 0x4493bb  (/out/package/main+0x4493bb)
    #2 0x449486  (/out/package/main+0x449486)
    #3 0x518ef2  (/out/package/main+0x518ef2)
    #4 0x5151f2  (/out/package/main+0x5151f2)
    #5 0x7f707b3dab96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
    #6 0x41cb09  (/out/package/main+0x41cb09)

0x602000000019 is located 0 bytes to the right of 9-byte region [0x602000000010,0x602000000019)
allocated by thread T0 here:
    #0 0x4dcbe8  (/out/package/main+0x4dcbe8)
    #1 0x5159db  (/out/package/main+0x5159db)
    #2 0x5194e0  (/out/package/main+0x5194e0)
    #3 0x515367  (/out/package/main+0x515367)
    #4 0x7f707b3dab96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b9

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

0
1
2
4AP0LIhQU=143
oBUmdxEaIHuyL8=48582
3
4
4AP0LIhQU=143
oBUmdxEaIHuyL8=48582
MiXRrfQ0KLG=-26856

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JOJ Answer