Record Case Detail

Notes

This function is in beta test. Please help improve it in the issues here.

Stderr

10 double
0 print
1 sort inc
2 append yZfqS2EMpb 0.3993577152006793
3 append SWoJwK1C6EzH 0.1536454957613631
4 append sK2FyT 0.11269829725799929
5 sort dec
=================================================================
==433==ERROR: AddressSanitizer: heap-buffer-overflow on address 0x60200000001a at pc 0x0000004995ac bp 0x7fff58c10b30 sp 0x7fff58c102e0
READ of size 11 at 0x60200000001a thread T0
    #0 0x4995ab  (/out/package/main+0x4995ab)
    #1 0x5159ce  (/out/package/main+0x5159ce)
    #2 0x518c2b  (/out/package/main+0x518c2b)
    #3 0x5153bd  (/out/package/main+0x5153bd)
    #4 0x7f3097e68b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
    #5 0x41cb09  (/out/package/main+0x41cb09)

0x60200000001a is located 0 bytes to the right of 10-byte region [0x602000000010,0x60200000001a)
allocated by thread T0 here:
    #0 0x4dcbe8  (/out/package/main+0x4dcbe8)
    #1 0x5159db  (/out/package/main+0x5159db)
    #2 0x5194e0  (/out/package/main+0x5194e0)
    #3 0x515367  (/out/package/main+0x515367)
    #4 0x7f3097e

Hints

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

Your Answer


        

JOJ Answer

0
1
2
3
4
5
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
6
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
sK2FyT=0.112698
SWoJwK1C6EzH=0.153645
yZfqS2EMpb=0.399358
7
8
9
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
IEL2KtGpsCr=0.795706
iRVsWglay7=0.863901
sK2FyT=0.112698
SWoJwK1C6EzH=0.153645
yZfqS2EMpb=0.399358