Record Case Detail

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5 int
0 append 4AP0LIhQU 143
1 append oBUmdxEaIHuyL8 48582
2 print
3 append MiXRrfQ0KLG -26856
4 print

=================================================================
==22==ERROR: LeakSanitizer: detected memory leaks

Direct leak of 24 byte(s) in 1 object(s) allocated from:
    #0 0x4dc930  (/out/package/main+0x4dc930)
    #1 0x5157d3  (/out/package/main+0x5157d3)
    #2 0x5152d7  (/out/package/main+0x5152d7)
    #3 0x7fb239742b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

SUMMARY: AddressSanitizer: 24 byte(s) leaked in 1 allocation(s).

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

0
1
2
4AP0LIhQU=143
oBUmdxEaIHuyL8=48582
3
4
4AP0LIhQU=143
oBUmdxEaIHuyL8=48582
MiXRrfQ0KLG=-26856

Notes

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JOJ Answer