Record Case Detail

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5 int
0 append 4AP0LIhQU 2
1 append oBUmdxEaIHuyL8 759
2 print
3 append MiXRrfQ0KLG -420
4 print

=================================================================
==487==ERROR: LeakSanitizer: detected memory leaks

Direct leak of 24 byte(s) in 1 object(s) allocated from:
    #0 0x4dc930  (/out/package/main+0x4dc930)
    #1 0x5157d3  (/out/package/main+0x5157d3)
    #2 0x5152d7  (/out/package/main+0x5152d7)
    #3 0x7fd20a3e0b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

SUMMARY: AddressSanitizer: 24 byte(s) leaked in 1 allocation(s).

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

0
1
2
4AP0LIhQU=2
oBUmdxEaIHuyL8=759
3
4
4AP0LIhQU=2
oBUmdxEaIHuyL8=759
MiXRrfQ0KLG=-420

Notes

Stderr

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JOJ Answer