Notes
This function is in beta test. Please help improve it in the issues
here.
10 str
0 print
1 append NU7lXPGFsMY4c 9rTQ3
2 append pn6YT 6GYaq
3 append GVacjbsA0 WITG
4 append 5BHyuqkgI0pvA uemH
5 append od95SR7fUu V32tu
6 append T41K8vRYxiS 78QD
7 append uNh0R1gO kuUH9
8 print
9 print
=================================================================
==491==ERROR: LeakSanitizer: detected memory leaks
Direct leak of 24 byte(s) in 1 object(s) allocated from:
#0 0x4dc930 (/out/package/main+0x4dc930)
#1 0x5157d3 (/out/package/main+0x5157d3)
#2 0x5152d7 (/out/package/main+0x5152d7)
#3 0x7fe9f7edab96 (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
SUMMARY: AddressSanitizer: 24 byte(s) leaked in 1 allocation(s).
Hints
Your answer may be identical to the JOJ answer in the first several lines.
However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.
Please double check your code to solve this problem and try again.
Your Answer
JOJ Answer
0 1 2 3 4 5 6 7 8 NU7lXPGFsMY4c=9rTQ3 pn6YT=6GYaq GVacjbsA0=WITG 5BHyuqkgI0pvA=uemH od95SR7fUu=V32tu T41K8vRYxiS=78QD uNh0R1gO=kuUH9 9 NU7lXPGFsMY4c=9rTQ3 pn6YT=6GYaq GVacjbsA0=WITG 5BHyuqkgI0pvA=uemH od95SR7fUu=V32tu T41K8vRYxiS=78QD uNh0R1gO=kuUH9