Record Case Detail

This function is in beta test. Please help improve it in the issues here.

10 double
0 print
1 sort inc
=================================================================
==90==ERROR: AddressSanitizer: heap-use-after-free on address 0x603000000048 at pc 0x000000517682 bp 0x7fff04991070 sp 0x7fff04991068
READ of size 8 at 0x603000000048 thread T0
    #0 0x517681  (/out/package/main+0x517681)
    #1 0x515301  (/out/package/main+0x515301)
    #2 0x7f46adf6ab96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
    #3 0x41ca39  (/out/package/main+0x41ca39)

0x603000000048 is located 8 bytes inside of 24-byte region [0x603000000040,0x603000000058)
freed by thread T0 here:
    #0 0x4dc720  (/out/package/main+0x4dc720)
    #1 0x516724  (/out/package/main+0x516724)
    #2 0x5152ed  (/out/package/main+0x5152ed)
    #3 0x7f46adf6ab96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

previously allocated by thread T0 here:
    #0 0x4dc8f0  (/out/package/main+0x4dc8f0)
    #1 0x515aba  (/out/package/main+0x515aba)
    #2 0x514fff  (/out/package/main+0x514fff)
    #3 0x7f46adf6ab96  (/lib/x86_64-linux-gnu/libc

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

0
1
2
3
4
5
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
6
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
sK2FyT=0.112698
SWoJwK1C6EzH=0.153645
yZfqS2EMpb=0.399358
7
8
9
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
IEL2KtGpsCr=0.795706
iRVsWglay7=0.863901
sK2FyT=0.112698
SWoJwK1C6EzH=0.153645
yZfqS2EMpb=0.399358

Notes

Stderr

Hints

Your Answer

JOJ Answer