Record Case Detail

This function is in beta test. Please help improve it in the issues here.

5 int
0 append 4AP0LIhQU 143
=================================================================
==437==ERROR: AddressSanitizer: heap-buffer-overflow on address 0x602000000019 at pc 0x0000004adafc bp 0x7ffef848f6a0 sp 0x7ffef848ee50
WRITE of size 10 at 0x602000000019 thread T0
    #0 0x4adafb  (/out/package/main+0x4adafb)
    #1 0x51588a  (/out/package/main+0x51588a)
    #2 0x515327  (/out/package/main+0x515327)
    #3 0x7fcad32a8b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
    #4 0x41cac9  (/out/package/main+0x41cac9)

0x602000000019 is located 0 bytes to the right of 9-byte region [0x602000000010,0x602000000019)
allocated by thread T0 here:
    #0 0x4dc980  (/out/package/main+0x4dc980)
    #1 0x515834  (/out/package/main+0x515834)
    #2 0x515327  (/out/package/main+0x515327)
    #3 0x7fcad32a8b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

SUMMARY: AddressSanitizer: heap-buffer-overflow (/out/package/main+0x4adafb) 
Shadow bytes around the buggy address:
  0x0c047fff7fb0: 00 00 00 00 00 00 00 00 00 00 00 0

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

0
1
2
4AP0LIhQU=143
oBUmdxEaIHuyL8=48582
3
4
4AP0LIhQU=143
oBUmdxEaIHuyL8=48582
MiXRrfQ0KLG=-26856

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JOJ Answer