Record Case Detail

This function is in beta test. Please help improve it in the issues here.

10 double
0 print
1 sort inc
2 append yZfqS2EMpb 0.3993577152006793
=================================================================
==401==ERROR: AddressSanitizer: heap-buffer-overflow on address 0x602000000019 at pc 0x0000004adafc bp 0x7ffdafabcac0 sp 0x7ffdafabc270
WRITE of size 11 at 0x602000000019 thread T0
    #0 0x4adafb  (/out/package/main+0x4adafb)
    #1 0x51588a  (/out/package/main+0x51588a)
    #2 0x515327  (/out/package/main+0x515327)
    #3 0x7f2c93404b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
    #4 0x41cac9  (/out/package/main+0x41cac9)

0x602000000019 is located 0 bytes to the right of 9-byte region [0x602000000010,0x602000000019)
allocated by thread T0 here:
    #0 0x4dc980  (/out/package/main+0x4dc980)
    #1 0x515834  (/out/package/main+0x515834)
    #2 0x515327  (/out/package/main+0x515327)
    #3 0x7f2c93404b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

SUMMARY: AddressSanitizer: heap-buffer-overflow (/out/package/main+0x4adafb) 
Shadow bytes around the buggy address:
  0x0c047fff7

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

0
1
2
3
4
5
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
6
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
sK2FyT=0.112698
SWoJwK1C6EzH=0.153645
yZfqS2EMpb=0.399358
7
8
9
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
IEL2KtGpsCr=0.795706
iRVsWglay7=0.863901
sK2FyT=0.112698
SWoJwK1C6EzH=0.153645
yZfqS2EMpb=0.399358

Notes

Stderr

Hints

Your Answer

JOJ Answer