Record Case Detail

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10 double
0 print
1 sort inc
2 append yZfqS2EMpb 0.3993577152006793
3 append SWoJwK1C6EzH 0.1536454957613631
4 append sK2FyT 0.11269829725799929
5 sort dec
6 sort inc
7 append IEL2KtGpsCr 0.7957063358982038
8 append iRVsWglay7 0.8639012165969916
9 print

=================================================================
==412==ERROR: LeakSanitizer: detected memory leaks

Direct leak of 144 byte(s) in 2 object(s) allocated from:
    #0 0x4dc980  (/out/package/main+0x4dc980)
    #1 0x51680c  (/out/package/main+0x51680c)
    #2 0x51537d  (/out/package/main+0x51537d)
    #3 0x7eff94d13b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

Direct leak of 62 byte(s) in 6 object(s) allocated from:
    #0 0x4dc980  (/out/package/main+0x4dc980)
    #1 0x51584d  (/out/package/main+0x51584d)
    #2 0x516b8e  (/out/package/main+0x516b8e)
    #3 0x51537d  (/out/package/main+0x51537d)
    #4 0x7eff94d13b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

Direct leak of 32 byte(s) in 1 object(s) allocated from:
    #0 0x4dc980  (/out/pa

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

0
1
2
3
4
5
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
6
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
sK2FyT=0.112698
SWoJwK1C6EzH=0.153645
yZfqS2EMpb=0.399358
7
8
9
yZfqS2EMpb=0.399358
SWoJwK1C6EzH=0.153645
sK2FyT=0.112698
IEL2KtGpsCr=0.795706
iRVsWglay7=0.863901
sK2FyT=0.112698
SWoJwK1C6EzH=0.153645
yZfqS2EMpb=0.399358

Notes

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JOJ Answer