Record Case Detail

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5 str
0 append xUfGb TeNdP
1 append FeSx0YRVlP2 Ms7o
2 append UZ3Fp1kzIbl7Xe w5QFz
3 append hITyrvAcZ W14N
4 print

=================================================================
==489==ERROR: LeakSanitizer: detected memory leaks

Direct leak of 43 byte(s) in 4 object(s) allocated from:
    #0 0x4dc980  (/out/package/main+0x4dc980)
    #1 0x51584d  (/out/package/main+0x51584d)
    #2 0x515327  (/out/package/main+0x515327)
    #3 0x7fc263bb9b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

Direct leak of 32 byte(s) in 1 object(s) allocated from:
    #0 0x4dc980  (/out/package/main+0x4dc980)
    #1 0x5155d7  (/out/package/main+0x5155d7)
    #2 0x51507f  (/out/package/main+0x51507f)
    #3 0x7fc263bb9b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

SUMMARY: AddressSanitizer: 75 byte(s) leaked in 5 allocation(s).

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

0
1
2
3
4
xUfGb=TeNdP
FeSx0YRVlP2=Ms7o
UZ3Fp1kzIbl7Xe=w5QFz
hITyrvAcZ=W14N

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JOJ Answer