Record Case Detail

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10 int
0 append vP3cQpMzLCmd -35084
1 empty
2 append hLQj5n68HzIy 49453
3 append kEey1tihW5RKzV 45500
4 append NBqFejKT -42778
5 append hWQ8lF 56352
6 append 6czWb9qQeVB -28268
7 append 9E3Goachd8JA 64267
8 append Vd53hgpyIqxv 54270
9 print

=================================================================
==491==ERROR: LeakSanitizer: detected memory leaks

Direct leak of 95 byte(s) in 8 object(s) allocated from:
    #0 0x4dc980  (/out/package/main+0x4dc980)
    #1 0x51584d  (/out/package/main+0x51584d)
    #2 0x515327  (/out/package/main+0x515327)
    #3 0x7f962c92fb96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

Direct leak of 32 byte(s) in 1 object(s) allocated from:
    #0 0x4dc980  (/out/package/main+0x4dc980)
    #1 0x5155d7  (/out/package/main+0x5155d7)
    #2 0x51507f  (/out/package/main+0x51507f)
    #3 0x7f962c92fb96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

SUMMARY: AddressSanitizer: 127 byte(s) leaked in 9 allocation(s).

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

0
1
false
2
3
4
5
6
7
8
9
vP3cQpMzLCmd=-35084
hLQj5n68HzIy=49453
kEey1tihW5RKzV=45500
NBqFejKT=-42778
hWQ8lF=56352
6czWb9qQeVB=-28268
9E3Goachd8JA=64267
Vd53hgpyIqxv=54270

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JOJ Answer