Notes
This function is in beta test. Please help improve it in the issues
here.
5 int 0 append 4AP0LIhQU 143 1 append oBUmdxEaIHuyL8 48582 2 print ================================================================= ==481==ERROR: AddressSanitizer: heap-buffer-overflow on address 0x602000000030 at pc 0x000000519899 bp 0x7ffebe431370 sp 0x7ffebe431368 READ of size 4 at 0x602000000030 thread T0 #0 0x519898 (/out/package/main+0x519898) #1 0x5151b2 (/out/package/main+0x5151b2) #2 0x7fda76ef2b96 (/lib/x86_64-linux-gnu/libc.so.6+0x21b96) #3 0x41cac9 (/out/package/main+0x41cac9) 0x602000000032 is located 0 bytes to the right of 2-byte region [0x602000000030,0x602000000032) allocated by thread T0 here: #0 0x4dc980 (/out/package/main+0x4dc980) #1 0x51616e (/out/package/main+0x51616e) #2 0x5169cf (/out/package/main+0x5169cf) #3 0x519a70 (/out/package/main+0x519a70) #4 0x515327 (/out/package/main+0x515327) #5 0x7fda76ef2b96 (/lib/x86_64-linux-gnu/libc.so.6+0x21b96) SUMMARY: AddressSanitizer: heap-buffer-overflow (/out/package/main+0x519898) Shadow by
Hints
Your answer may be identical to the JOJ answer in the first several lines.
However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.
Please double check your code to solve this problem and try again.
Your Answer
JOJ Answer
0 1 2 4AP0LIhQU=143 oBUmdxEaIHuyL8=48582 3 4 4AP0LIhQU=143 oBUmdxEaIHuyL8=48582 MiXRrfQ0KLG=-26856