Notes
This function is in beta test. Please help improve it in the issues
here.
5 str
0 append xUfGb TeNdP
1 append FeSx0YRVlP2 Ms7o
2 append UZ3Fp1kzIbl7Xe w5QFz
3 append hITyrvAcZ W14N
4 print
=================================================================
==481==ERROR: LeakSanitizer: detected memory leaks
Direct leak of 43 byte(s) in 4 object(s) allocated from:
#0 0x4dc980 (/out/package/main+0x4dc980)
#1 0x51584d (/out/package/main+0x51584d)
#2 0x515327 (/out/package/main+0x515327)
#3 0x7fb033e1cb96 (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
SUMMARY: AddressSanitizer: 43 byte(s) leaked in 4 allocation(s).
Hints
Your answer may be identical to the JOJ answer in the first several lines.
However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.
Please double check your code to solve this problem and try again.
Your Answer
JOJ Answer
0 1 2 3 4 xUfGb=TeNdP FeSx0YRVlP2=Ms7o UZ3Fp1kzIbl7Xe=w5QFz hITyrvAcZ=W14N