Record Case Detail

Notes

This function is in beta test. Please help improve it in the issues here.

Stderr

 pwd: /out/package
ppid: 4117
   1: WRITELN echo 321 > 1.txt
   2: WRITELN <
   3: WRITELN 1.txt cat
   4: WRITELN ls
   5: WRITELN exit
exit: 1

Hints

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

Your Answer

mumsh $ mumsh $ =================================================================
==4118==ERROR: AddressSanitizer: stack-buffer-underflow on address 0x7ffd75652bbf at pc 0x00000051cebc bp 0x7ffd7564d960 sp 0x7ffd7564d958
READ of size 1 at 0x7ffd75652bbf thread T0
    #0 0x51cebb  (/out/package/mumsh_memory_check+0x51cebb)
    #1 0x515a5f  (/out/package/mumsh_memory_check+0x515a5f)
    #2 0x51533c  (/out/package/mumsh_memory_check+0x51533c)
    #3 0x7f6b92f2ab96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
    #4 0x41cc69  (/out/package/mumsh_memory_check+0x41cc69)

Address 0x7ffd75652bbf is located in stack of thread T0 at offset 31 in frame
    #0 0x51503f  (/out/package/mumsh_memory_check+0x51503f)

  This frame has 1 object(s):
    [32, 1056) 'cmd' <== Memory access at offset 31 underflows this variable
HINT: this may be a false positive if your program uses some custom stack unwind mechanism or swapcontext
      (longjmp and C++ exceptions *are* supported)
SUMMARY: AddressSanitizer: stack-buffer-underflow (

JOJ Answer

mumsh $ mumsh $ > 321
mumsh $ 1.txt
driver
mumsh
mumsh_memory_check
mumsh $ exit