Record Case Detail

This function is in beta test. Please help improve it in the issues here.

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

dict_items([(<generator object ParticleFilter.initializeUniformly.<locals>.<genexpr> at 0x7f1bca2950f8>, 1.0), ((2, 7), 0.0), ((4, 7), 0.0), ((1, 3), 0.0), ((5, 4), 0.0), ((3, 3), 0.0), ((5, 5), 0.0), ((5, 6), 0.0), ((5, 7), 0.0), ((1, 4), 0.0), ((1, 5), 0.0), ((1, 6), 0.0), ((2, 3), 0.0), ((4, 3), 0.0), ((1, 7), 0.0), ((5, 3), 0.0), ((3, 7), 0.0), ((3, 5), 0.0)])
dict_items([((2, 7), 0.0588235294118), ((4, 7), 0.0588235294118), ((1, 3), 0.0588235294118), ((3, 3), 0.0588235294118), ((1, 6), 0.0588235294118), ((5, 6), 0.0588235294118), ((5, 7), 0.0588235294118), ((5, 4), 0.0588235294118), ((1, 4), 0.0588235294118), ((1, 5), 0.0588235294118), ((3, 5), 0.0588235294118), ((2, 3), 0.0588235294118), ((4, 3), 0.0588235294118), ((1, 7), 0.0588235294118), ((3, 7), 0.0588235294118), ((5, 3), 0.0588235294118), ((5, 5), 0.0588235294118), (<generator object ParticleFilter.initializeUniformly.<locals>.<genexpr> at 0x7f1bca2950f8>, 0.0)])
*** None) Distribution deviated at move 0 by 1.0588 (squared norm) from the correct an

*** None) Particle filter full test: 0 inference errors.
*** PASS: ./test_cases/q7/1-ParticlePredict.test

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