Record Case Detail

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==19602==ERROR: AddressSanitizer: heap-use-after-free on address 0x602000000158 at pc 0x000000517009 bp 0x7ffe1747e780 sp 0x7ffe1747e778
READ of size 8 at 0x602000000158 thread T0
    #0 0x517008  (/out/package/ex7+0x517008)
    #1 0x51526a  (/out/package/ex7+0x51526a)
    #2 0x7f6e868f1b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
    #3 0x41ca29  (/out/package/ex7+0x41ca29)

0x602000000158 is located 8 bytes inside of 16-byte region [0x602000000150,0x602000000160)
freed by thread T0 here:
    #0 0x4dc710  (/out/package/ex7+0x4dc710)
    #1 0x51663a  (/out/package/ex7+0x51663a)
    #2 0x5152f7  (/out/package/ex7+0x5152f7)
    #3 0x7f6e868f1b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

previously allocated by thread T0 here:
    #0 0x4dc8e0  (/out/package/ex7+0x4dc8e0)
    #1 0x515ae0  (/out/package/ex7+0x515ae0)
    #2 0x5151a6  (/out/package/ex7+0x5151a6)
    #3 0x7f6e868f1b96  (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)

SUMMARY: AddressSan

Your answer may be identical to the JOJ answer in the first several lines.

However, the main problem you meet now is Runtime Error. And the exit code of your program is 1, which should be 0.

Please double check your code to solve this problem and try again.

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1 
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0
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1 D 
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1
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j 1 D 
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2
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G j 1 D 
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3
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j 1 D 
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4
0
5
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j 1 
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6
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j 1 
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7
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j 1 5 
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8
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l j 1 5 
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9
4
10
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l j 1 
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11
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l j 1 z 
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12
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5 l j 1 z 
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13
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5 l j 1 z S 
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14
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5 l j 1 z S k 
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15
7
16
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I 5 l j 1 z S k 
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Notes

Stderr

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Your Answer

JOJ Answer